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Assembly • Section 9.4

Double-Shear Joint Assembly & Pin Analysis

Pin double shear ($P_{us}$), plastic bending ($P_{ub}$), balanced weak-pin design, and clevis gap effects

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1. Double-Shear Clevis Joint Architecture

A standard aerospace structural pinned joint consists of a single center male lug (tongue, thickness $t_2$) inserted between two symmetric female cheek lugs (clevis ears, thickness $t_1$) separated by an assembly clearance gap $g$ on each side, joined by a transverse shear pin of diameter $D_p$.

Per USAF AFFDL-TR-69-42 Section 9.4, the combined joint capacity depends on the interaction between pin shear strength, pin bending stiffness, and lug bearing plasticity.

2. Pin Shear Strength (Equation 9-12)

In a symmetrical double-shear clevis, the pin must fail across two simultaneous transverse cross-sections located in the gaps between the male lug and female ears:

$$P_{us} = 2 \cdot A_{pin} \cdot F_{su,pin} = 2 \cdot \left(\frac{\pi D_p^2}{4}\right) \cdot F_{su,pin} = \frac{\pi}{2} D_p^2 \cdot F_{su,pin} \approx 1.571 \cdot D_p^2 \cdot F_{su,pin}$$
AFFDL-TR-69-42 Equation (9-12): Ultimate pin double-shear allowable.

where $D_p$ is the nominal pin diameter and $F_{su,pin}$ is the pin material ultimate shear allowable (typically $0.60 \times F_{tu}$ for high-strength steel pins like 4340 or 17-4PH).

3. Pin Plastic Bending Strength (Equations 9-14 & 9-15)

Because the male lug and female lugs are spaced apart by clearances ($g$), the applied load produces a severe transverse bending moment across the center of the pin. The ultimate bending capacity accounts for full plastic hinge development:

$$M_{ult} = k_b \cdot \left(\frac{\pi D_p^3}{32}\right) \cdot F_{tu,pin}$$
AFFDL-TR-69-42 Equation (9-14): Ultimate plastic bending moment of cylindrical pin.

where $k_b$ is the pin plastic bending coefficient (Section 9.4.3):

  • $k_b = 1.56$: Standard aerospace coefficient for ductile steel pins ($\varepsilon_u > 5\%$). Represents the plastic shape factor of a solid circular cross section ($1.70$) reduced slightly for shear deflection coupling.
  • $k_b = 1.00$: Brittle pins ($\varepsilon_u \le 5\%$), restricted to elastic section modulus ($Z = \pi D_p^3 / 32$).

The nominal pin bending load allowable $P_{ub}$ across the nominal span is:

$$P_{ub} = \frac{2 \cdot M_{ult}}{\frac{t_1}{2} + \frac{t_2}{4} + g}$$
AFFDL-TR-69-42 Equation (9-15): Nominal pin bending strength.

4. Strong Pin vs. Balanced Weak-Pin Behavior

Section 9.4 classifies joint assemblies into two distinct structural regimes:

Classification Physical Behavior Governing Joint Capacity ($P_{u,J}$)
Strong Pin
($P_{ub} \ge P_{u,LB}$ or $P_{ub} \ge P_{us}$)
The pin is thick and stiff relative to the lugs. It deflects negligibly under load; bearing pressure remains evenly distributed across the full thickness of male and female lugs. $P_{u,J} = \min\left(2 P_{u,LB1},\; P_{u,LB2},\; P_{us}\right)$
Weak Pin (Balanced Design)
($P_{ub} < P_{u,LB}$)
The pin flexes significantly under load. This flexibility concentrates bearing contact near the gap edges, peeling away from outer faces. The joint reaches a plastic equilibrium governed by effective contact widths $b_1$ and $b_2$. Evaluated using USAF Equations (9-16) and (9-18a/b):
$P_{ub,max} = 2 C \left[\sqrt{\frac{P_{ub}}{C}\left(\frac{t_1}{2} + \frac{t_2}{4} + g\right) + g^2} - g\right]$

5. Critical Impact of Assembly Gap Spacing ($g$)

⚠
Keep Assembly Gaps Small: The gap distance $g$ appears directly in the bending moment arm denominator. Increasing the gap from $0.03\text{ in}$ to $0.15\text{ in}$ can decrease pin bending capacity by over 30%, often flipping a joint from strong-pin to weak-pin governance.

Calculate Lug Margins of Safety Online

Apply AFFDL-TR-69-42 Chapter 9 analysis with real-time geometry diagrams, digitized curve interpolation, and pin-clevis checks.